Question

7 целых 1/7 × 3целых 1/2,10целых1/22 × 1целых 1/3,1целых 7/10× 3 целых 1/3,8целых2/3×1целых2/13

Answer 1

Вот ответ, держи, вроде бы все верно, 11 класс))

Answer 2

It looks like you've provided a mathematical expression in Russian. Let's break it down and solve it step by step.

The expression you've provided is: 7 целых 1/7 × 3 целых 1/2, 10 целых 1/22 × 1 целых 1/3, 1 целых 7/10 × 3 целых 1/3, 8 целых 2/3 × 1 целых 2/13

This expression consists of multiplication operations between mixed numbers. To solve it, we'll start by converting all the mixed numbers into improper fractions and then proceed with the multiplication.

Let's convert the mixed numbers into improper fractions: 7 целых 1/7 = (7 * 7 + 1)/7 = 50/7 3 целых 1/2 = (3 * 2 + 1)/2 = 7/2 10 целых 1/22 = (10 * 22 + 1)/22 = 221/22 1 целых 1/3 = (1 * 3 + 1)/3 = 4/3 1 целых 7/10 = (1 * 10 + 7)/10 = 17/10 3 целых 1/3 = (3 * 3 + 1)/3 = 10/3 8 целых 2/3 = (8 * 3 + 2)/3 = 26/3 1 целых 2/13 = (1 * 13 + 2)/13 = 15/13

Now, let's perform the multiplication: (50/7) × (7/2) × (221/22) × (4/3) × (17/10) × (10/3) × (26/3) × (15/13)

After multiplying all the fractions together, we get the result of the expression. Let's calculate the result.