Question

Велосипедист за 3 часа проехал расстояние от посёлка до города со скоростью 16 км\ч. На обратный путь он затратил 4 часа. На сколько километров в час меньше была скорость велосипедиста на обратном пути?

Answer 1

1) 16*3=48(км)- от поселка до города
2) 48:4=12(км/ч)- скорость на обратном пути
3) 16-12=4(км/ч)- меньше

Answer 2

Calculation of the Speed Difference

To calculate the difference in speed between the cyclist's outbound and return journeys, we need to compare the time taken for each journey and the distance covered.

Given: - Time taken for the outbound journey: 3 hours - Time taken for the return journey: 4 hours - Speed during the outbound journey: 16 km/h

To find the distance covered during each journey, we can use the formula:

Distance = Speed × Time

For the outbound journey: Distance = 16 km/h × 3 hours = 48 km

For the return journey: Distance = Speed × Time = ? (unknown)

To find the speed during the return journey, we can rearrange the formula:

Speed = Distance / Time

Substituting the known values: Speed = 48 km / 4 hours = 12 km/h

Therefore, the speed of the cyclist during the return journey was 12 km/h less than the speed during the outbound journey.