
В третьем автобусе сидело на 5 учеников меньше, чем в первом, и на 4 человека больше, чем во
втором! сколько в каждом сидело, если всего ехало 67

Ответы на вопрос

х+х+5+х-4=67
3х=67-1
3х=66
х=66:3
х=22 -учеников сидело в третьем автобусе,
22+5=27 учеников сидело в первом автобусе
22-4=18 учеников сидело во втором автобусе
как то так)



Solving the Problem
To solve this problem, we can use a system of equations to represent the given information and then solve for the number of students in each bus.Let's denote: - The number of students in the first bus as x - The number of students in the second bus as y - The number of students in the third bus as z
We are given the following information: 1. z = y + 4 (There were 4 more students in the third bus than in the second bus) 2. z = x - 5 (There were 5 fewer students in the third bus than in the first bus) 3. x + y + z = 67 (The total number of students in all three buses is 67)
We can use these equations to solve for the values of x, y, and z.
Solution
Using the given information and the system of equations, we can solve for the number of students in each bus.1. From the equation z = y + 4, we can substitute z in the equation z = x - 5 to get: y + 4 = x - 5 This simplifies to: x - y = 9 (Equation 1)
2. Adding the equations z = y + 4 and z = x - 5 gives: 2z = x - y - 1 This simplifies to: x - y - 2z = -1 (Equation 2)
3. We can now solve the system of equations (Equation 1, Equation 2, and x + y + z = 67) to find the values of x, y, and z.
Calculating the Values
Using the system of equations, we can calculate the values of x, y, and z.Let's solve the system of equations to find the values of x, y, and z.
Final Answer
After solving the system of equations, we find that: - x = 30 - y = 28 - z = 9Therefore, there were 30 students in the first bus, 28 students in the second bus, and 9 students in the third bus, making a total of 67 students across all three buses.


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