Question

Всего в 2-х классах 52 ученика. в одном классе на 2 ученика меньше,чем в другом.сколько учеников в каждом классе?

Answer 1

Пусть в одном классе x учеников, тогда во втором будет x-2.

Составим и решим уравнение:

x+(x-2)=52

x+x=52+2

2x=54

$x= \frac{54}{2}$

$x=27$ уч. - в одном классе

$27-2=25$ уч. - в другом классе

Answer 2

1 класс,? на 2 ученика меньше чем во 2    всего 52 ученика
2 класс ?
 Пусть х учеников в 1 классе, тогда:
1 класс х
2 класс х+2   всего 52 ученика
составим и решим уравнение:
1) х+х+2=52
    2х=52-2
    2х=50
    х=50:2
    х=25       25 учеников в 1 классе
2) 25+2=27(уч)- во 2 классе
ответ: 25 учеников; 27 учеников

Answer 3

Solving for the Number of Students in Each Class

To solve this problem, we can use a system of equations. Let's denote the number of students in the first class as x and the number of students in the second class as y. We know that the total number of students in both classes is 52, and the second class has 2 fewer students than the first class. This can be represented by the following equations:

1. x + y = 52 (total number of students) 2. y = x - 2 (the second class has 2 fewer students than the first class)

Solving the System of Equations

To solve the system of equations, we can substitute the value of y from the second equation into the first equation and solve for x.

Substituting y = x - 2 into x + y = 52: x + (x - 2) = 52 2x - 2 = 52 2x = 54 x = 27

Now that we have found the value of x, we can find the value of y using the second equation: y = x - 2 y = 27 - 2 y = 25

Answer

So, there are 27 students in one class and 25 students in the other class.