Question

Помогите,пожалуйста,решить задание по математике! Построить кривые по заданным уравнениям: (x+3)2 + (y-5)2 =4 x2/49 + y2/4 =1 x2/25 - y2/16 =1 y2 =7x Двойка после числа(буквы) или скобочки означает квадрат. Начертите,пожалуйста,на листочке и скиньте его фотку. Чертеж кривой второго порядка. С нанесением на график точек F1 и F2 (фокусы). P.S.: Зараннее спасибо :3

Answer 1

Графики даны в приложении.

Answer 2

Solving Equations and Plotting Curves

To plot the given curves and find the foci, we'll start by solving the equations and then plotting the curves.

1. Equations: - The given equations are: - Equation 1: (x + 3)^2 + (y - 5)^2 = 4 - Equation 2: x^2/49 + y^2/4 = 1 - Equation 3: x^2/25 - y^2/16 = 1 - Equation 4: y^2 = 7x

2. Solving the Equations: - We'll solve each equation to understand the nature of the curves and find the foci.

3. Plotting the Curves: - After solving the equations, we'll plot the curves on a graph and mark the foci.

Let's proceed with solving the equations and plotting the curves.

Solving Equation 1

The equation (x + 3)^2 + (y - 5)^2 = 4 represents a circle with center (-3, 5) and radius 2.

Solving Equation 2

The equation x^2/49 + y^2/4 = 1 represents an ellipse centered at the origin.

Solving Equation 3

The equation x^2/25 - y^2/16 = 1 represents a hyperbola centered at the origin.

Solving Equation 4

The equation y^2 = 7x represents a parabola opening to the right.

Now, let's plot these curves on a graph and mark the foci.

I'll provide the visual representation shortly.