Question

Лена и Саша играют в кости, они бросают по одному разу. Выигрывает тот кто выбросил больше очков если выпало поровну, то наступает ничья. В сумме выпало 8 очков найдите вероятность того , что Лена выйграла.

Answer 1

Можливі такі варіанти подій :  6/2, 5/3, 4/4, 3/5, 2/6.  Р=m/n   

m- кількість подій,які сприяють (6/2, 5/3 )

n - кількість усіх можливих подій (6/2, 5/3, 4/4, 3/5, 2/6)

отже вірогідність того, що Лєна виграла Р=⅖ або можна записати Р=0,4 .

Answer 2

Probability of Lena Winning in a Single Dice Throw

In a single dice throw, Lena and Sasha are playing to see who gets more points. If they both get the same number of points, it's a tie. The total points obtained are 8. We need to find the probability of Lena winning.

The possible combinations of points that add up to 8 are: - (1, 7) - (2, 6) - (3, 5) - (4, 4)

The total number of possible outcomes when throwing a single dice is 6, as there are 6 faces on a standard dice.

Calculation of Probability

The probability of Lena winning can be calculated by finding the number of favorable outcomes for Lena and dividing it by the total number of possible outcomes.

The favorable outcomes for Lena winning are: - (1, 7) - (2, 6) - (3, 5)

So, there are 3 favorable outcomes for Lena winning.

Probability Calculation

The probability of Lena winning can be calculated as follows: Probability (Lena winning) = Favorable outcomes / Total possible outcomes Probability (Lena winning) = 3 / 6 Probability (Lena winning) = 0.5

Therefore, the probability of Lena winning in a single dice throw is 0.5 or 50%.