Question

11y-((9y-5)-(6y+3))=8

Answer 1

11у-(9у-5-6у-3)=11у-3у+8=8у+8
8у+8=8
8у=0
у=0
Ответ: у=0

Answer 2

To solve the equation 11y - ((9y - 5) - (6y + 3)) = 8, we can follow the order of operations (PEMDAS/BODMAS) and simplify the expression step by step.

Step 1: Simplify the innermost parentheses. Inside the parentheses, we have (9y - 5) - (6y + 3). Let's simplify this expression: = 9y - 5 - 6y - 3 = 9y - 6y - 5 - 3 = 3y - 8

Now, the equation becomes 11y - (3y - 8) = 8.

Step 2: Remove the outer parentheses by distributing the negative sign. Distributing the negative sign inside the parentheses, we get: = 11y - 3y + 8 = 8

Step 3: Combine like terms on both sides of the equation. Combine the y-terms on the left side: = 8y + 8 = 8

Step 4: Isolate the variable. To isolate the variable y, we need to move the constant term on the left side to the right side by subtracting 8 from both sides: 8y + 8 - 8 = 8 - 8 8y = 0

Step 5: Solve for y. To solve for y, we divide both sides of the equation by 8: 8y/8 = 0/8 y = 0

Therefore, the solution to the equation 11y - ((9y - 5) - (6y + 3)) = 8 is y = 0.