Question

Два катера движутся навстречу друг другу.Сейчас между ними25 км.Скорость одного из них составляет 7/8 скорости другого.Найдите скорость катера,если известно,что они встретятся через 5/12 часа.

Answer 1

Эта задача решается уравнением:
x*5/12+7/8x*5/12=25
(1+7/8)*5/12*x=25
15/8*5/12x=25
x=25:25/32
x=32
7/8x=7/8*32=28
Ответ: Скорость первого катера 28км/ч , скорость второго 32км/ч 
Тоже самое задали)

Answer 2

Problem Analysis

We are given that two boats are moving towards each other. The distance between them is 25 km. The speed of one boat is 7/8 times the speed of the other boat. We need to find the speed of the boat if they meet after 5/12 hours.

Solution

Let's assume the speed of the slower boat is x km/h. Then the speed of the faster boat will be (7/8)x km/h.

We know that distance = speed × time.

The distance covered by the slower boat in 5/12 hours is (x × 5/12) km.

The distance covered by the faster boat in 5/12 hours is ((7/8)x × 5/12) km.

Since they are moving towards each other, the sum of the distances covered by both boats should be equal to the total distance between them.

So, we can write the equation:

(x × 5/12) + ((7/8)x × 5/12) = 25

Simplifying the equation:

(5/12)x + (35/96)x = 25

Multiplying both sides by the least common multiple of 12 and 96, which is 96:

(80/192)x + (35/192)x = 25 × 96

Simplifying further:

(115/192)x = 2400

To find the value of x, we can multiply both sides by the reciprocal of 115/192, which is 192/115:

x = (2400 × 192/115)

Evaluating the expression:

x ≈ 4000/3 ≈ 1333.33 km/h

Therefore, the speed of the boat is approximately 1333.33 km/h.

Answer

The speed of the boat is approximately 1333.33 km/h.