Question

Задача.В двух мешках было 82кг муки.После того как из одного мешка в другой пересыпали 14кг,в первом мешке муки оказалось в 3 раза меньше,чем во втором.Сколько килограммов муки было в каждом мешке первоначально?

Answer 1

X+y=82
x-14/3+y=82

x=82-y
(82-y-14+3y)/3=82

68+2y=246
2y=178
y=89
x=-7

Answer 2

Problem Analysis

We are given that there were 82 kg of flour in two bags. After transferring 14 kg from one bag to the other, the amount of flour in the first bag became three times smaller than the amount in the second bag. We need to find the initial amount of flour in each bag.

Solution

Let's assume that the initial amount of flour in the first bag is x kg. Since the amount of flour in the first bag became three times smaller after transferring 14 kg, the amount of flour in the first bag after the transfer is (x - 14) kg.

According to the problem, the amount of flour in the first bag after the transfer is three times smaller than the amount in the second bag. Therefore, we can write the equation:

(x - 14) = (1/3) * (82 - x)

Now, let's solve this equation to find the value of x.

(x - 14) = (1/3) * (82 - x) 3(x - 14) = 82 - x 3x - 42 = 82 - x 4x = 124 x = 31

So, the initial amount of flour in the first bag was 31 kg.

To find the initial amount of flour in the second bag, we can subtract the amount transferred from the total initial amount:

82 - 14 = 68

Therefore, the initial amount of flour in the second bag was 68 kg.

Answer

The initial amount of flour in each bag was 31 kg in the first bag and 68 kg in the second bag.