Question

Ширина прямоугольника 8 м.Это в 3 раза меньше,чем длина. Найти периметр и площадь прямоугольника.

Answer 1

Длина = Ширина*3 = 8*3 =24 м
Периметр = 2(Ширина+Длина)=2(8+24)=64м
Площадь = Ширина*Длина=8*24=192 м 

Answer 2

8x3=24м-длина
(24+8)х2=64-периметр
24х8=192-площадь

Answer 3

Problem Analysis

We are given that the width of a rectangle is 8 meters, which is 3 times smaller than the length of the rectangle. We need to find the perimeter and area of the rectangle.

Solution

Let's assume the length of the rectangle is L. According to the given information, the width is 3 times smaller than the length, so the width is L/3.

Perimeter of the Rectangle

The perimeter of a rectangle is given by the formula: P = 2 * (length + width).

Substituting the values, we have: P = 2 * (L + L/3) = 2 * (4L/3) = 8L/3.

Therefore, the perimeter of the rectangle is 8L/3.

Area of the Rectangle

The area of a rectangle is given by the formula: A = length * width.

Substituting the values, we have: A = L * (L/3) = L^2/3.

Therefore, the area of the rectangle is L^2/3.

Calculation

To find the perimeter and area of the rectangle, we need to find the value of L.

From the given information, we know that the width is 8 meters, which is 3 times smaller than the length. So, we can set up the equation: 8 = L/3.

Solving for L, we have: L = 24.

Now, we can substitute the value of L into the formulas for perimeter and area.

Perimeter:

P = 8L/3 = 8 * 24/3 = 64 meters.

Area:

A = L^2/3 = 24^2/3 = 576/3 = 192 square meters.

Therefore, the perimeter of the rectangle is 64 meters and the area of the rectangle is 192 square meters.