Question

# в классе 29 учащихся. Рост каждого из них выражается целым числом сантиметров. Средний рост всех, кроме самого высокого ученика, равен 149 4/7 см. Каков рост самого высокого ученика, если средний рост всех учащихся выражается целым числом?

Answer 1

1) Сумма роста 28 учащихся класса S=28*149 4/7=4188 см.
2) Средний рост 29 учащихся - Z (целое число), рост самого высокого ученика L.
(4188+L)/29=Z
L=Z*29-4188, число Z - сопоставимо со средним ростом 28 учащихся и равно ближайшему большему числу. Z=150
L=150*29-4188=162 см.

Answer 2

Finding the Height of the Tallest Student

To find the height of the tallest student, we need to use the information given in the question. Let's break down the information step by step:

1. The class consists of 29 students. 2. The height of each student is expressed in whole numbers of centimeters. 3. The average height of all the students, excluding the tallest student, is 149 4/7 cm.

To find the height of the tallest student, we can use the concept of averages. The average height of all the students, excluding the tallest student, is given as 149 4/7 cm. This means that if we add up the heights of all the students (excluding the tallest one) and divide it by the number of students (excluding the tallest one), we will get an average of 149 4/7 cm.

Let's denote the height of the tallest student as x. We can set up the following equation:

(29 * 149 4/7) + x = (29 + 1) * 149

Simplifying the equation:

(29 * 149) + (4/7 * 29) + x = 30 * 149

Now, let's solve for x:

(29 * 149) + (4/7 * 29) + x = 30 * 149

(29 * 149) + (4/7 * 29) + x = 4470

4291 + (4/7 * 29) + x = 4470

(4/7 * 29) + x = 179

To find the value of x, we need to calculate (4/7 * 29) and subtract it from 179:

(4/7 * 29) = 16

179 - 16 = 163

Therefore, the height of the tallest student is 163 cm.

Please note that the above calculation is based on the information provided in the question and assumes that the average height of all the students, excluding the tallest one, is expressed as a mixed fraction (149 4/7 cm).