Question

Из города одновременно в одном направлении выехали автобус со скоростью 70 км.ч и легковая машина, скорость который была больше скорости автобуса. через 3 часа легковая машина опередила автобус на 60км. с какой скоростью она ехала?

Answer 1

70×3=210
210+60=270
270÷3=90

Answer 2

Problem Analysis

We are given that a bus and a car start from the same city in the same direction. The bus has a speed of 70 km/h, and the car has a speed greater than the bus. After 3 hours, the car overtakes the bus and is 60 km ahead. We need to find the speed of the car.

Solution

Let's assume the speed of the car is x km/h.

After 3 hours, the car has covered a distance of 3x km, and the bus has covered a distance of 3 * 70 = 210 km.

Since the car overtakes the bus and is 60 km ahead, we can set up the following equation:

3x - 210 = 60

Simplifying the equation:

3x = 270

Dividing both sides by 3:

x = 90

Therefore, the speed of the car is 90 km/h.

Answer

The car was traveling at a speed of 90 km/h.