Question

Пожалуйста ответьте математика 6 класс. 1) 42+75+(-14) +(-26) +56 2) 12+(-20) -(-11) -(-6) -10 3) 3целых 5/12 - (- 1 целая 1/3) +(-4целых 3/8). Помогите пожалуйста

Answer 1

113
2) -1
Третье не знаю

Answer 2

Ответ:

Пошаговое объяснение:

1) = 42 + 75 - 14 - 26 + 56 = 133

2) = 12 - 20 + 11 + 6 - 10 = -1

3) = 3. 5/12 + 1. 1/3 - 4. 3/8 =

3. 10/24 + 1. 8/24 - 4. 9/24 =

4. 18/24 - 4. 9/24 = 9/24 = 3/8

Answer 3

Math Problems for 6th Grade

Let's solve the math problems you provided step by step:

1) 42 + 75 + (-14) + (-26) + 56

To solve this expression, we can simply add all the numbers together:

42 + 75 + (-14) + (-26) + 56 = 133

So the answer is 133.

2) 12 + (-20) - (-11) - (-6) - 10

To solve this expression, we need to be careful with the signs. Remember that subtracting a negative number is the same as adding a positive number. Let's simplify it:

12 + (-20) - (-11) - (-6) - 10 = 12 - 20 + 11 + 6 - 10 = -1

So the answer is -1.

3) 3 and 5/12 - (-1 and 1/3) - (-4 and 3/8)

To solve this expression, we need to subtract the second and third numbers from the first number. Let's convert all the mixed numbers to improper fractions:

3 and 5/12 = 3 + 5/12 = 36/12 + 5/12 = 41/12

-1 and 1/3 = -1 + 1/3 = -3/3 + 1/3 = -2/3

-4 and 3/8 = -4 + 3/8 = -32/8 + 3/8 = -29/8

Now, let's substitute these values into the expression:

41/12 - (-2/3) - (-29/8)

To subtract a negative number, we can change it to addition:

41/12 + 2/3 + 29/8

To add these fractions, we need to find a common denominator. The least common multiple of 12, 3, and 8 is 24. Let's convert all the fractions to have a denominator of 24:

(41/12) * (2/2) = 82/24

(2/3) * (8/8) = 16/24

(29/8) * (3/3) = 87/24

Now, let's substitute these values into the expression:

82/24 + 16/24 + 87/24 = 185/24

So the answer is 185/24.

I hope this helps! Let me know if you have any further questions.