Question

В трех автобусах ехало 68 ребят.во втором автобусе детей было на 6 больше чем в первом и на 8 меньше чем в третим.сколько детей ехало в каждом автобусе

Answer 1

х - ехало в первом, тогда х+6  - ехало во втором, и х+6+8 = х+14  - в третьем.

х + (х+6) + (х+14) = 68

3х + 20 = 68

3х = 48

х = 16,  х+6 = 22,  х + 14 = 30

Ответ: в 1 автобусе ехало 16 детей; во 2 ехало 22 и в 3 ехало 30.

Answer 2

Problem Analysis

We are given that there were a total of 68 children in three buses. The second bus had 6 more children than the first bus, and 8 fewer children than the third bus. We need to determine the number of children in each bus.

Solution

Let's assume the number of children in the first bus is x.

According to the given information: - The second bus had 6 more children than the first bus, so the number of children in the second bus is x + 6. - The second bus had 8 fewer children than the third bus, so the number of children in the third bus is x + 6 + 8 = x + 14.

The total number of children in the three buses is 68, so we can write the equation:

x + (x + 6) + (x + 14) = 68

Simplifying the equation:

3x + 20 = 68

Subtracting 20 from both sides:

3x = 48

Dividing both sides by 3:

x = 16

Therefore, there were 16 children in the first bus, 16 + 6 = 22 children in the second bus, and 16 + 14 = 30 children in the third bus.

Answer

There were 16 children in the first bus, 22 children in the second bus, and 30 children in the third bus.