Question

Не могу решить помоги пожайлуста y=2cosx на отрезке п деленное на 3, и 3п деленное на 2

Answer 1

У= 2соs (пи/3)= 2косинус (1/2)=1
у=2соs (3пи/2)= 2косинус (0)=0

Answer 2

Solving y=2cosx on the Intervals π/3 and 3π/2

To solve the equation y=2cosx on the intervals π/3 and 3π/2, we can use trigonometric identities and properties to find the values of x that satisfy the equation.

First, let's consider the general form of the cosine function: cosx = adjacent/hypotenuse

Given that y=2cosx, we can rearrange the equation to solve for cosx: cosx = y/2

Now, we can use the inverse cosine function to find the values of x that satisfy the equation.

Finding x for y=2cosx on the Interval π/3

Using the inverse cosine function, we have: x = arccos(y/2)

Substituting the value of π/3 for y: x = arccos(π/3/2)

Finding x for y=2cosx on the Interval 3π/2

Similarly, for the interval 3π/2: x = arccos(3π/2/2)

Let's calculate the values of x for both intervals using the given values of y.

Calculating x for y=2cosx on the Interval π/3

Using the given value of y=π/3: x = arccos(π/3/2)

Calculating x for y=2cosx on the Interval 3π/2

Using the given value of y=3π/2: x = arccos(3π/2/2)

We can now calculate the values of x for both intervals and provide the solutions.

Let's calculate the values of x for the given intervals and the equation y=2cosx.