Question

Дети собрали две модели лунохо- дов. Один работал 12 минут, другой – 18 минут. Причём второй преодолел расстояние на 30 метров больше, чем первый. Сколько метров преодолел каждый луноход? С краткой записью пожалуйста ​

Answer 1

Ответ:

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Answer 2

Ответ:

1) 18-12=6 (На сколько второй луноход работал дольше)

2) 30:6=5 м. (Преодоление расстояния за 1 миниту)

3) 18*5= 90 м. (Преодоления расстояния второго лунохода)

4) 90-30= 60 м. (Преодоления расстояния первого лунохода)

Пошаговое объяснение:

Ответ: Первый луноход преодолел расстояние 60 метров.Второц луноход преодолел расстояние 90 метров.

Пж можешь дать лучший ответ.Я старался.

Answer 3

Problem Analysis

We are given two lunar rovers (lunokhods) and their respective operating times. The first rover operated for 12 minutes, while the second rover operated for 18 minutes. Additionally, the second rover traveled a distance that was 30 meters greater than the first rover. We need to determine the distance traveled by each rover.

Solution

Let's assume that the first rover traveled a distance of x meters. Since the second rover traveled a distance that was 30 meters greater than the first rover, the distance traveled by the second rover can be represented as x + 30 meters.

We know that the speed of an object is equal to the distance traveled divided by the time taken. Therefore, we can set up the following equations:

For the first rover: Speed of the first rover = x meters / 12 minutes

For the second rover: Speed of the second rover = (x + 30) meters / 18 minutes

Since the speed of an object remains constant, we can equate the two speeds:

x / 12 = (x + 30) / 18

To solve this equation, we can cross-multiply:

18x = 12(x + 30)

Simplifying the equation:

18x = 12x + 360

6x = 360

x = 60

Therefore, the first rover traveled a distance of 60 meters and the second rover traveled a distance of 60 + 30 = 90 meters.

Answer

The first lunar rover traveled a distance of 60 meters and the second lunar rover traveled a distance of 90 meters.