
Катер шел 3ч против течения реки и 2ч по течению. Какой путь прошел катер за эти 5ч, если
собственая скорость катера 18,6км/ч , а скорость течения реки 1,3км/ч

Ответы на вопрос

V против течения = 18,6-1,3=17,3
S=2*19,9+3*17,3=39,8+51,9=91,7 км



Problem Analysis
We are given the following information: - The boat traveled for 3 hours against the current of the river. - The boat traveled for 2 hours with the current of the river. - The boat's own speed is 18.6 km/h. - The speed of the river's current is 1.3 km/h.We need to calculate the total distance traveled by the boat in these 5 hours.
Calculation
To calculate the distance traveled by the boat, we can use the formula:Distance = Speed x Time
Let's calculate the distance traveled against the current and with the current separately.
Distance traveled against the current: - Speed of the boat = 18.6 km/h - Speed of the current = 1.3 km/h - Time = 3 hours
Distance against the current = (Speed of the boat - Speed of the current) x Time
Distance against the current = (18.6 km/h - 1.3 km/h) x 3 hours
Distance against the current = 17.3 km/h x 3 hours
Distance against the current = 51.9 km
Distance traveled with the current: - Speed of the boat = 18.6 km/h - Speed of the current = 1.3 km/h - Time = 2 hours
Distance with the current = (Speed of the boat + Speed of the current) x Time
Distance with the current = (18.6 km/h + 1.3 km/h) x 2 hours
Distance with the current = 19.9 km/h x 2 hours
Distance with the current = 39.8 km
Now, let's calculate the total distance traveled by adding the distances against and with the current:
Total distance traveled = Distance against the current + Distance with the current
Total distance traveled = 51.9 km + 39.8 km
Total distance traveled = 91.7 km
Therefore, the boat traveled a total distance of 91.7 km in these 5 hours.
Answer
The boat traveled a total distance of 91.7 km in these 5 hours.

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