Question

Срочно помогите пожалуйста даю 30 балов у сплаві було золото срібло і домішки. Золота 30% домішок 5% а срібла на 5 мг більше ніж золота. Знайти вагу сплаву​

Answer 1

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Your question is in Ukrainian, and it translates to:

Answer in detail. Please help urgently give 30 points in the alloy there was gold silver and impurities. Gold 30% impurities 5% and silver 5 mg more than gold. Find the weight of the alloy.

To solve this problem, we need to use some algebra. Let x be the weight of the alloy in mg. Then we have the following equations:

- The amount of gold in the alloy is 0.3x mg. - The amount of impurities in the alloy is 0.05x mg. - The amount of silver in the alloy is x - 0.3x - 0.05x + 5 mg, which is 0.65x + 5 mg.

The sum of these amounts is equal to the weight of the alloy, so we have:

x = 0.3x + 0.05x + 0.65x + 5

Simplifying this equation, we get:

0.35x = 5

Dividing both sides by 0.35, we get:

x = 5 / 0.35

x = 14.2857

Therefore, the weight of the alloy is approximately 14.2857 mg.