Question

Дано точки D,E i F такі , що DE =2см, EF=4см, DF=6см. Скільки площин можна провести через точки D, E I F?

Answer 1

Ответ:

DE+EF=2+4=6, DF=DE+EF, следовательно эти три не могут образовывать треугольник (т.к. любая сторона треугольника меньше суммы длин двух остальных сторон), и, следовательно, лежат на одной прямой. Через прямую можно провести бесконечное количество плоскостей

Answer 2

Number of Planes through Points D, E, and F

To determine the number of planes that can be drawn through points D, E, and F, we need to consider the properties of three non-collinear points in three-dimensional space.

In three-dimensional space, any three non-collinear points determine a unique plane. This means that for any three points that are not on the same line, there is exactly one plane that contains all three points.

In the given scenario, points D, E, and F are not collinear, as they form a triangle with sides DE, EF, and DF. Therefore, we can conclude that there is exactly one plane that can be drawn through points D, E, and F.

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