Question

Conroy made a big rubber band ball using between 29 and 100 rubber bands. If the number of rubber bands could be shared equally into both three and five groups, how many might he have used?​

Answer 1

Ответ:

To find the number of rubber bands that Conroy might have used, we need to find a number that is both divisible by 3 and 5. This is equivalent to finding a number that is divisible by their least common multiple, which is 15.

The smallest multiple of 15 that is between 29 and 100 is 30. Therefore, Conroy might have used 30 rubber bands.

Пошаговое объяснение:

Answer 2

To find the possible number of rubber bands Conroy used, we need to find a number that can be evenly divided by both three and five. This means we are looking for a number that is a multiple of both three and five.

The multiples of three are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99, ...

The multiples of five are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100, ...

Looking at the list of multiples of both three and five, we can see that the numbers that are common to both lists are 15, 30, 45, 60, 75, 90. Since Conroy's number of rubber bands falls between 29 and 100, the only possible number of rubber bands that he could have used is 30 or 45. These are the only numbers that can be evenly divided by both three and five in the given range. Therefore, Conroy might have used either 30 or 45 rubber bands to make his rubber band ball.