
Задачка срочно! Авто ехал 0.9ч пл асфальту и 0.6ч по грунтовке, проехав всего 93.6км С какой
скорость ехал авто по асфальту если по грунтовке он ехал 48км/ч

Ответы на вопрос

ответ 1)48×0.6=28.8км проехал по грунтовой дороге
2)93.6-28.8=64.8км ехал по асфальтированной дороге
3)64.8÷0.9=72км/ч скорость по асфальтированной дороге



Problem Analysis
To solve this problem, we need to find the speed at which the car was traveling on the asphalt road. We are given the following information: - The car traveled on asphalt for 0.9 hours. - The car traveled on a dirt road for 0.6 hours. - The total distance traveled was 93.6 km. - The speed on the dirt road was 48 km/h.Solution
Let's assume the speed on the asphalt road is x km/h. We can use the formula speed = distance / time to find the speed on the asphalt road.The distance traveled on the asphalt road can be calculated by subtracting the distance traveled on the dirt road from the total distance: distance on asphalt = total distance - distance on dirt road
The time traveled on the asphalt road can be calculated by subtracting the time traveled on the dirt road from the total time: time on asphalt = total time - time on dirt road
Now we can substitute the values into the formula to find the speed on the asphalt road: x = (distance on asphalt) / (time on asphalt)
Let's calculate the values step by step.
Calculation
Given: - Total distance = 93.6 km - Time on dirt road = 0.6 hours - Speed on dirt road = 48 km/hFirst, let's calculate the distance on the asphalt road: distance on asphalt = total distance - distance on dirt road distance on asphalt = 93.6 km - 48 km = 45.6 km
Next, let's calculate the time on the asphalt road: time on asphalt = total time - time on dirt road time on asphalt = 0.9 hours - 0.6 hours = 0.3 hours
Finally, let's calculate the speed on the asphalt road: x = (distance on asphalt) / (time on asphalt) x = 45.6 km / 0.3 hours = 152 km/h
Answer
The car was traveling at a speed of 152 km/h on the asphalt road.Please let me know if you need any further assistance!


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