Question

Sin2pix/3=0 PLEASEEEEEEEEEEEEEE

Answer 1

$\sin\frac23\pi x=0;\\ \frac23\pi x=\pi n,\ n\in Z;\\ \frac23x=n,\ n\in Z;\\ x=\frac32n,\ n\in Z.$

Answer 2

To solve the equation sin(2πx/3) = 0, we need to find the values of x that satisfy this equation.

The equation sin(2πx/3) = 0 means that the sine of the angle (2πx/3) is equal to zero. In other words, we are looking for the values of x for which the angle (2πx/3) has a sine of zero.

The sine function is zero at certain angles, such as 0, π, 2π, etc. These angles are multiples of π. So, we can write the equation as:

2πx/3 = nπ,

where n is an integer.

To find the values of x, we can solve for x in terms of n:

x = (3nπ)/(2π),

Simplifying the expression, we get:

x = (3n)/2.

Therefore, the values of x that satisfy the equation sin(2πx/3) = 0 are given by x = (3n)/2, where n is an integer.

For example, if n = 0, then x = 0. If n = 1, then x = 3/2. If n = -1, then x = -3/2, and so on.

I hope this helps! Let me know if you have any further questions.