Question

2. Яке з наведених чисел ділиться і на 2 і на 9 одночасно? А. 2436 Б. 8316 В. 6518 Г.8145

Answer 1

Ответ:

Ответ: 8316

Объяснение:

для того, чтобы число делилось и на 2 на 9 нужно, чтобы оно было четным и сумма его цифр делилась на 9.

2436 -=2+4+3+6 = 15 (не делится на 9)

8316= 8+3+1+6 - 18 (делится на 9)

6518 = 6+5+1+8 = 20 (не делится на 9)

Пошаговое объяснение:

Я СТАРАЛАСЬ

Answer 2

Let's check which of the given numbers is divisible by both 2 and 9.

A. 2436: To check if a number is divisible by 2, we see if the last digit is even, which it is (6). So, 2436 is divisible by 2. To check if a number is divisible by 9, we find the sum of its digits and see if the sum is divisible by 9. In this case, 2 + 4 + 3 + 6 = 15, which is not divisible by 9. Therefore, 2436 is not divisible by both 2 and 9.

B. 8316: Again, we check if it is divisible by 2 by looking at the last digit, which is even (6), so it is divisible by 2. To check for divisibility by 9, we find the sum of its digits: 8 + 3 + 1 + 6 = 18. Since 18 is divisible by 9, 8316 is divisible by both 2 and 9.

C. 6518: The last digit is even (8), so the number is divisible by 2. However, when we find the sum of its digits, 6 + 5 + 1 + 8 = 20, which is not divisible by 9. So, 6518 is only divisible by 2, not by both 2 and 9.

D. 8145: As the last digit is odd (5), 8145 is not divisible by 2. Therefore, it cannot be divisible by both 2 and 9.

Therefore, only option B, 8316, is divisible by both 2 and 9.