Question

Два кондитерських цехи за день мали разом виготовити 300 тортів. Коли перший цех виконав 55 % свого завдання, а другий – 60 % свого, виявилося,що перший цех виготовив на 27 тортів більше, ніж другий. По скільки тортів мав виготовити кожен цех? ​

Answer 1

Відповідь:180;120

Покрокове пояснення:

Answer 2

Problem Analysis

We have two confectionery factories that together produce 300 cakes in one day. The first factory completes 55% of its task, while the second factory completes 60% of its task. It is known that the first factory produces 27 more cakes than the second factory. We need to find out how many cakes each factory should have produced.

Solution

Let's assume that the first factory should have produced x cakes, and the second factory should have produced y cakes.

According to the given information: - The first factory completed 55% of its task, so it produced 55% of x cakes, which is 0.55x cakes. - The second factory completed 60% of its task, so it produced 60% of y cakes, which is 0.60y cakes. - The first factory produced 27 more cakes than the second factory, so we can write the equation: 0.55x = 0.60y + 27.

To solve this equation, we can rearrange it to isolate one variable and substitute it into the other equation. Let's isolate x:

0.55x = 0.60y + 27

x = (0.60y + 27) / 0.55

Now we can substitute this value of x into the equation 0.55x = 0.60y + 27:

0.55 * ((0.60y + 27) / 0.55) = 0.60y + 27

Simplifying this equation will give us the value of y:

0.60y + 27 = 0.60y + 27

The equation is true for any value of y. This means that there are infinitely many solutions to this problem. We cannot determine the exact number of cakes each factory should have produced based on the given information.

Therefore, we cannot provide a specific answer to the question "How many cakes should each factory have produced?"