Question

ТЕРМІНОВО!!! Визначте додатне значення м, за якого один з коренів рівняння x²-(2m-4)x+16=0 буде на 6 більший за інший 2. З 3 хлопців та 3 дівчат добирають 4 учасників. Скільки є варіантів вибору ​

Answer 1

Ответ:Х=0 так как умножение на ноль дает ноль а там еще и отрицательные то все уже становиться понатным

Пошаговое объяснение:

Answer 2

Positive Value of m in the Equation x² - (2m-4)x + 16 = 0

To find the positive value of m in the equation x² - (2m-4)x + 16 = 0, where one of the roots is 6 greater than the other, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, the equation is x² - (2m-4)x + 16 = 0. Comparing this to the general form ax² + bx + c = 0, we can see that a = 1, b = -(2m-4), and c = 16.

We are given that one of the roots is 6 greater than the other. Let's assume that the smaller root is x1 and the larger root is x2. According to the given information, we have:

x2 = x1 + 6

Using the quadratic formula, we can substitute the values of a, b, and c into the formula and solve for x1 and x2. Since we are looking for a positive value of m, we will consider the discriminant (b² - 4ac) to be greater than or equal to 0.

Substituting the values into the quadratic formula, we get:

x1 = [(2m-4) - √((2m-4)² - 4(1)(16))] / (2(1))

x2 = [(2m-4) + √((2m-4)² - 4(1)(16))] / (2(1))

Simplifying the equations further, we have:

x1 = (2m-4 - √(4m² - 16m + 16 - 64)) / 2

x2 = (2m-4 + √(4m² - 16m + 16 - 64)) / 2

To find the positive value of m, we need to solve for m when x1 and x2 satisfy the condition x2 = x1 + 6.

Substituting the values of x1 and x2 into the equation x2 = x1 + 6, we get:

[(2m-4) + √(4m² - 16m + 16 - 64)] / 2 = [(2m-4) - √(4m² - 16m + 16 - 64)] / 2 + 6

Simplifying the equation further, we have:

[(2m-4) + √(4m² - 16m - 48)] / 2 = [(2m-4) - √(4m² - 16m - 48)] / 2 + 6

To solve this equation, we can multiply both sides by 2 to eliminate the denominators:

**[(2m-4) + √(4m² -