Question

Мама оставила сыну на 2 дня несколько яблок. В первый день он съел половину всех яблок и еще пол-яблока. Во второй день он съел половину оставшихся яблок и ещё пол-яблока. После этого у него осталость одно яблоко. Сколько яблок мама оставила? Сколько он сьел в перый день? (поогите мама оставила 7 яблок так у мя с зади книги написано а сколько но сьел не знаю) 50 баллов за ответ я не вру

Answer 1

Решение:
Пусть всего было Х яблок. Тогда в первый день мальчик съел (Х+1)/2 яблок.
Осталось: Х-(Х+1)/2=(Х-1)/2 яблок.
Во второй день мальчик съел [(Х-1)/2]:2+1/2=(Х-1)/4+1/2=(Х+1)/4.
Значит остаток от первого дня минус съеденные яблоки во второй день равно 1 яблоко или:
(Х-1)/2-(Х+1)/4=1
2Х-2-Х-1=4
Х=7.
Ответ: было 7 яблок. В первый день мальчик съел 4 яблока.

Answer 2

Problem Analysis

The problem states that a mother left her son with several apples for two days. On the first day, the son ate half of all the apples and half of another apple. On the second day, he ate half of the remaining apples and half of another apple. After that, he had one apple left. We need to determine how many apples the mother left and how many the son ate on the first day.

Solution

Let's assume that the mother left x apples for her son.

On the first day, the son ate half of all the apples, which is x/2, and half of another apple, which is 1/2. So, on the first day, the son ate a total of x/2 + 1/2 apples.

On the second day, the son ate half of the remaining apples, which is (x - (x/2 + 1/2))/2, and half of another apple, which is 1/2. After that, he had one apple left, so we can set up the equation:

(x - (x/2 + 1/2))/2 + 1/2 = 1

Simplifying the equation:

(x - (x/2 + 1/2))/2 = 1 - 1/2

(x - (x/2 + 1/2))/2 = 1/2

Multiplying both sides of the equation by 2:

x - (x/2 + 1/2) = 1

Simplifying further:

2x - x - 1 = 2

x - 1 = 2

x = 3

Therefore, the mother left 3 apples for her son.

On the first day, the son ate 3/2 + 1/2 = 2 apples.

Answer

The mother left 3 apples for her son, and he ate 2 apples on the first day.