Question

Arcsin √3/2+arccos⁡(-1/2)+arctg√3

Answer 1

arcsin √3/2+arccos⁡(-1/2)+arctg√3=π/3+2π/3+π/3=4π/3

Answer 2

You've got yourself a tasty mathematical expression there! Let's break it down step by step.

1. arcsin(√3/2): This is asking for the angle whose sine is √3/2. The answer is π/3.

2. arccos(-1/2): This is the angle whose cosine is -1/2. The answer is 2π/3.

3. arctg(√3): This is the arctangent of √3. The answer is π/3.

Now, add them up:

π/3 + 2π/3 + π/3 = 4π/3.

So, the value of your expression is 4π/3.