Question

3×х=568-242,а×80=140÷7​

Answer 1

Непонятно это 2 уравнения или что?

решаю:

3×x=568-242

Вычитать числа

3x=326

Разделяем обе части уравнения на 3, получаем:

x=$\frac{326}{3}$

Второе уравнение

a×80=140÷7

Избавляемся от знаком умножения и выполняем деление:

80a=20

разделяем обе части уравнения на 80, получаем:

a=$\frac{1}{4}$

Answer 2

To solve these equations, you can follow these steps:

1. Solve the equation 3x = 568 - 242:

   Subtract 242 from 568 to get: 3x = 326

   Now, divide both sides by 3 to solve for x: x = 326 / 3 x = 108.67 (rounded to two decimal places)

2. Solve the equation a * 80 = 140 ÷ 7:

   First, calculate 140 ÷ 7: 140 ÷ 7 = 20

   Now, you have the equation: a * 80 = 20

   To solve for a, divide both sides by 80: a = 20 / 80 a = 0.25

So, the solutions to the equations are:

1. x ≈ 108.67
2. a = 0.25

Answer 3

Let's solve the two equations:

1. 3x = 568 - 242
2. a * 80 = 140 ÷ 7

For the first equation: 3x = 568 - 242

Subtract 242 from 568: 3x = 326

Now, divide both sides by 3 to solve for x: x = 326 / 3 x ≈ 108.67 (rounded to two decimal places)

For the second equation: a * 80 = 140 ÷ 7

Divide 140 by 7: a * 80 = 20

Now, divide both sides by 80 to solve for a: a = 20 / 80 a = 1/4

So, the solutions are: x ≈ 108.67 a = 1/4