Question

Heeeeeeeelpppp -2cos(p/3-x/6)-кореньиз2=0

Answer 1

Решение в приложении.

Answer 2

Ответ:x =  13π\2+ 12πk, k∈Z

           x =  - 5π\2+ 12πn, n∈Z

Пошаговое объяснение:

-2 cos(π\3 - x\6) - √2 = 0

cos(x\6 - π\3) = -√2\2. (в скобках поменяли засчет четности функции косинус)

х/6 - π/3 = ±(π - arccos √2\2) + 2πk, k∈Z

х/6 - π/3 = ±(π -π\4) + 2πk, k∈Z

х/6 - π/3 = ± 3π\4 + 2πk, k∈Z

1) х/6 - π/3 = 3π\4 + 2πk, k∈Z

х/6  =  3π\4 +π/3 + 2πk, k∈Z

x\6 = 13π\12+ 2πk, k∈Z

x =  13π\2+ 12πk, k∈Z

2) х/6 - π/3 = -3π\4 + 2πn, n∈Z

х/6  =  -3π\4 +π/3 + 2πn, n∈Z

x\6 = - 5π\12+ 2πn, n∈Z

x =  - 5π\2+ 12πn, n∈Z

Answer 3

It seems like you've provided an equation, but it's a bit unclear. Let's first clarify and solve the equation for you.

The equation you've written is: -2cos(p/3 - x/6) - √2 = 0

I assume you want to solve for 'x' in this equation. To do that, we'll first isolate the cosine term and then solve for 'x'. Here are the steps:

1. Add √2 to both sides of the equation: -2cos(p/3 - x/6) = √2

2. Divide both sides by -2 to isolate the cosine term: cos(p/3 - x/6) = -√2/2

3. Now, you want to find the values of 'x' that satisfy this equation. The cosine function is equal to -√2/2 at certain angles, typically 45 degrees and 225 degrees, in degrees or π/4 and 5π/4 in radians. So, you have:

p/3 - x/6 = π/4 + 2nπ OR p/3 - x/6 = 5π/4 + 2nπ

Here, 'n' is an integer representing the periodic nature of the cosine function.

4. Now, solve each of these equations for 'x': For π/4 + 2nπ: x = p/3 - 6(π/4 + 2nπ)

For 5π/4 + 2nπ: x = p/3 - 6(5π/4 + 2nπ)

These are the solutions for 'x' in terms of 'n'. You can plug in integer values for 'n' to find the corresponding values of 'x'. Please note that 'p' in the equation should probably be replaced with 'π' to represent the constant pi (approximately 3.14159). If 'p' represents a variable, you will need to provide its specific value for a numeric solution.