Question

3•(x-2)+5•(x+2)=28 10 blov

Answer 1

Вот,все на фото, пожалуйста,отметь как лучшее)

Answer 2

3•(x-2)+5•(x+2)=28

3х-6+5х+10=28

3х+5х=28+6-10

8х=24

х=24/8

х=3

Answer 3

To solve for the value of "x" in the equation 3(x-2) + 5(x+2) = 28, you can follow these steps:

1. First, distribute the constants outside the parentheses: 3(x) - 3(2) + 5(x) + 5(2) = 28

2. Now, simplify the equation by combining like terms: 3x - 6 + 5x + 10 = 28

3. Combine the "x" terms on one side of the equation and the constants on the other side: 3x + 5x - 6 + 10 = 28

4. Combine the "x" terms: 8x - 6 + 10 = 28

5. Combine the constants: 8x + 4 = 28

6. To isolate "x," subtract 4 from both sides of the equation: 8x + 4 - 4 = 28 - 4

7. Simplify the equation: 8x = 24

8. Finally, divide both sides by 8 to solve for "x": 8x/8 = 24/8

9. Simplify further: x = 3

So, the solution to the equation 3(x-2) + 5(x+2) = 28 is x = 3.