Question

8 17\36 + x + 7 31\36 = 25 1\36

Answer 1

8 17/36+x+ 7 31/36-25 1/36=0. x+15 48/36 - 25 1/36. x - 10 47/36=0. x= 10 47/36

Answer 2

To solve the equation $\frac{8}{17} + x + \frac{7}{31} = \frac{25}{36}$, you can start by finding a common denominator for the fractions on the left-hand side. The common denominator for 17 and 31 is 527 (the least common multiple of 17 and 31). So, rewrite the fractions with a common denominator:

$\frac{8}{17}$ becomes $\frac{8 \cdot 31}{17 \cdot 31} = \frac{248}{527}$.

$\frac{7}{31}$ remains the same.

Now the equation becomes:

$\frac{248}{527} + x + \frac{7}{31} = \frac{25}{36}$.

To solve for $x$, you can isolate $x$ on one side of the equation:

$\frac{248}{527} + x + \frac{7}{31} - \frac{7}{31} = \frac{25}{36} - \frac{7}{31}$.

Now, simplify both sides:

$\frac{248}{527} + x = \frac{775}{1116} - \frac{496}{527}$.

Now, subtract the fractions on the right-hand side:

$\frac{248}{527} + x = \frac{279}{1116}$.

Next, subtract $\frac{248}{527}$ from both sides to isolate (x:

$x = \frac{279}{1116} - \frac{248}{527}$.

To subtract these fractions, you'll need a common denominator. The least common multiple of 1116 and 527 is 584292. Rewrite both fractions with this common denominator:

$x = \frac{279 \cdot 527}{1116 \cdot 527} - \frac{248 \cdot 1116}{527 \cdot 1116}$.

Now, you can subtract the fractions:

$x = \frac{147033}{584292} - \frac{276768}{584292}$.

Subtract the numerators:

$x = \frac{147033 - 276768}{584292}$.

Now, subtract the numerators:

$x = \frac{-129735}{584292}$.

You can simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 3:

$x = \frac{-43245}{194764}$.

So, the solution to the equation is $x = \frac{-43245}{194764}$.