Question

12x + 12 2x^2 - 6x X^2 + 3x^ - 10 9x^2 - 25

Answer 1

$12x + 12 = 12(x + 1) \\ 2 {x}^{2} - 6x = 2x(x - 3) \\ {x}^{2} + 3 {x}^{ - 10} = {x}^{2} + 3 \times \frac{1}{ {x}^{10} } = {x}^{2} + \frac{3}{ {x}^{10} } = \frac{ {x}^{12} + 3 }{ {x}^{10} } \\ 9 {x}^{2} - 25 = {3}^{2} {x}^{2} - {5}^{2} = (3x - 5)(3x + 5)$

Answer 2

1) x=-12/12

x=-1

2) x(2x-6)=0; x=0 или x=3

3) D=7^2; x1,2=(-3+-7)/2= -5; -2

4) x= +-5/3

Answer 3

It seems like you have provided a series of mathematical expressions, but there are some formatting issues and unclear symbols in your input. I'll try to interpret and simplify each expression as best as I can:

1. 12x + 12: This is a simple linear expression, and it can be simplified by factoring out the common factor of 12: 12x + 12 = 12(x + 1)

2. 2x^2 - 6x: This is a quadratic expression. If you'd like to factor it further, you can factor out a common factor of 2x: 2x(x - 3)

3. x^2 + 3x^ - 10: It appears there might be a formatting issue in this expression. It seems like you want to write x^2 + 3x - 10. To factor this quadratic expression, you can look for two numbers that multiply to -10 and add up to 3. Those numbers are 5 and -2: (x + 5)(x - 2)

4. 9x^2 - 25: This is a difference of squares, which can be factored as follows: 9x^2 - 25 = (3x + 5)(3x - 5)

So, in summary:

1. 12x + 12 = 12(x + 1)
2. 2x^2 - 6x = 2x(x - 3)
3. x^2 + 3x - 10 = (x + 5)(x - 2)
4. 9x^2 - 25 = (3x + 5)(3x - 5)