Question

3/2+(-103/1)=-8/3+7/4=5/3+(-16/5)=​

Answer 1

Ответ:

Пошаговое объяснение:

3/2+(-103/1) = 3/2 - 103 = 1целая 1/2 - 102целых 2/2 = - 101 целых 1/2

-8/3 + 7/4 = - 1целых 20/12 + 1целая 9/12 = - 11/12

5/3 + (-16/5) = 1целая 10/15 - 2целых 18/15 = - 1целая 8/15

Answer 2

Let's calculate each of these expressions step by step:

1. $\frac{3}{2} + \left(\frac{-103}{1}\right)$:

   To add fractions, you need a common denominator. In this case, the common denominator is 2.

   $\frac{3}{2} + \left(\frac{-103 \cdot 2}{1 \cdot 2}\right) = \frac{3}{2} + \left(\frac{-206}{2}\right)$

   Now, you can add the fractions:

   $\frac{3}{2} - \frac{206}{2} = \frac{-203}{2}$

2. $\frac{-8}{3} + \frac{7}{4}$:

   To add fractions with different denominators, you need to find a common denominator. In this case, the least common denominator is 12.

   $\frac{-8}{3}$ can be converted to an equivalent fraction with a denominator of 12:

   $\frac{-8}{3} \cdot \frac{4}{4} = \frac{-32}{12}$

   Now, you can add the fractions:

   $\frac{-32}{12} + \frac{7}{4}$

   To add these fractions, they both need to have the same denominator (which is 12):

   $\frac{-32}{12} + \frac{7 \cdot 3}{4 \cdot 3} = \frac{-32}{12} + \frac{21}{12}$

   Now, you can add the fractions:

   $\frac{-32}{12} + \frac{21}{12} = \frac{-32 + 21}{12} = \frac{-11}{12}$

3. $\frac{5}{3} + \left(\frac{-16}{5}\right)$:

   To add fractions with different denominators, you need to find a common denominator. In this case, the least common denominator is 15.

   $\frac{5}{3}$ can be converted to an equivalent fraction with a denominator of 15:

   $\frac{5}{3} \cdot \frac{5}{5} = \frac{25}{15}$

   Now, you can add the fractions:

   $\frac{25}{15} + \frac{-16}{5}$

   To add these fractions, they both need to have the same denominator (which is 15):

   $\frac{25}{15} + \frac{-16 \cdot 3}{5 \cdot 3} = \frac{25}{15} + \frac{-48}{15}$

   Now, you can add the fractions:

   $\frac{25}{15} + \frac{-48}{15} = \frac{25 - 48}{15} = \frac{-23}{15}$

So, the results of the three expressions are:

1. $\frac{3}{2} + \left(\frac{-103}{1}\right) = \frac{-203}{2}$
2. $\frac{-8}{3} + \frac{7}{4} = \frac{-11}{12}$