Question

(5x-2)²= (7a+3b)²= (9a-2)²= (7x-4)²= (6a-2b)²= 25a²-49= 16x²-81= 64a²-25b²= (5a-4)(5a+4)= (9a-1)(1+9a)= (7a+3)(3-7a)=

Answer 1

Сразу пишу ответ там просто нужно подставить формулу
1)25х^2-20х+4
2)49а^2+42ab+9b^2
3)81a^2-36a+4
4)49x^2-56x+16
5)36a^2-24ab+4b^2
6)(5a-7)(5a+7)
7)(4x-9)(4x+9)
8)2(32a^2-25b)
9)25a^2-16
10)81a^2-1
11)9-49a^2

Answer 2

(5х-2)2= 25х2-20х+4
(7а+3b)2= 49a2+42ab+9b2
(9a-2)2=81a2-36a+4

(7x-4)2=49x2-56x+16
25a2-49=(5a-7)(5a+7)
16x2-81=(4x-9)(4x+9
64a2-25b2=(8a-5b)(8a+5b)
(5a-4)(5a+4)=25a2-16
(9a-1)(1+9a)=81a2-1
(7a+3)(3-7a)=9-49a2

Answer 3

Let's simplify each of the expressions step by step:

1. (5x-2)² This is a simple square of a binomial: (5x-2)² = (5x-2)(5x-2) = 25x² - 10x - 10x + 4 = 25x² - 20x + 4

2. (7a+3b)² Similarly, square the binomial: (7a+3b)² = (7a+3b)(7a+3b) = 49a² + 21ab + 21ab + 9b² = 49a² + 42ab + 9b²

3. (9a-2)² Square the binomial: (9a-2)² = (9a-2)(9a-2) = 81a² - 18a - 18a + 4 = 81a² - 36a + 4

4. (7x-4)² Square the binomial: (7x-4)² = (7x-4)(7x-4) = 49x² - 28x - 28x + 16 = 49x² - 56x + 16

5. (6a-2b)² Square the binomial: (6a-2b)² = (6a-2b)(6a-2b) = 36a² - 12ab - 12ab + 4b² = 36a² - 24ab + 4b²

6. 25a² - 49 This is the difference of squares: 25a² - 49 = (5a)² - 7² = (5a - 7)(5a + 7)

7. 16x² - 81 This is also the difference of squares: 16x² - 81 = (4x)² - 9² = (4x - 9)(4x + 9)

8. 64a² - 25b² This is the difference of squares: 64a² - 25b² = (8a)² - (5b)² = (8a - 5b)(8a + 5b)

9. (5a-4)(5a+4) This is another difference of squares: (5a-4)(5a+4) = (5a)² - 4² = 25a² - 16

10. (9a-1)(1+9a) This is a difference of squares as well: (9a-1)(1+9a) = (9a)² - 1² = 81a² - 1

11. (7a+3)(3-7a) This is another difference of squares: (7a+3)(3-7a) = (7a)² - 3² = 49a² - 9

So, the simplified expressions are:

1. 25x² - 20x + 4
2. 49a² + 42ab + 9b²
3. 81a² - 36a + 4
4. 49x² - 56x + 16
5. 36a² - 24ab + 4b²
6. (5a - 7)(5a + 7)
7. (4x - 9)(4x + 9)
8. (8a - 5b)(8a + 5b)
9. 25a² - 16
10. 81a² - 1
11. 49a² - 9