Question

4 1/5*5 7/9+(4 1/5)*3 5/9-4 1/5*1 2/9​

Answer 1

4 1/5 * 5 7/9 + 4 1/5 * 3 5/9 - 4 1/5 * 1 2/9 =

= 4 1/5 * (5 7/9 + 3 5/9 + 1 2/9) =

= 4 1/5 * 9 14/9 =

= 4 1/5 * 10 5/9 =

= 21/5 * 95/9 =

= 44 1/3

Ответ: 44 1/3

Answer 2

Let's break down the given expression step by step:

$4 \frac{1}{5} \times 5 \frac{7}{9} + (4 \frac{1}{5}) \times 3 \frac{5}{9} - 4 \frac{1}{5} \times 1 \frac{2}{9}$

First, let's convert the mixed numbers into improper fractions:

$4 \frac{1}{5} = \frac{4 \times 5}{5} + \frac{1}{5} = \frac{20}{5} + \frac{1}{5} = \frac{21}{5}$

$5 \frac{7}{9} = \frac{5 \times 9}{9} + \frac{7}{9} = \frac{45}{9} + \frac{7}{9} = \frac{52}{9}$

$3 \frac{5}{9} = \frac{3 \times 9}{9} + \frac{5}{9} = \frac{27}{9} + \frac{5}{9} = \frac{32}{9}$

$1 \frac{2}{9} = \frac{1 \times 9}{9} + \frac{2}{9} = \frac{9}{9} + \frac{2}{9} = \frac{11}{9}$

Now the expression becomes:

$\frac{21}{5} \times \frac{52}{9} + \left(\frac{21}{5}\right) \times \frac{32}{9} - \left(\frac{21}{5}\right) \times \frac{11}{9}$

Next, multiply the fractions:

$\frac{(21 \times 52)}{(5 \times 9)} + \frac{(21 \times 32)}{(5 \times 9)} - \frac{(21 \times 11)}{(5 \times 9)}$

Simplify the fractions:

$\frac{1092}{45} + \frac{672}{45} - \frac{231}{45}$

Now, add and subtract the fractions:

$\frac{1092 + 672 - 231}{45}$

$= \frac{1533}{45}$

Now, simplify the fraction:

$= 34 \frac{3}{45}$

So, the simplified result of the given expression is $34 \frac{3}{45}$.