Question

(7−...)(7+...) = 492−25

Answer 1

(7−х)(7+х) = 492−25

49-х²=418

-х²=418

х²=-418

уравнение не имеет действительных корней

Answer 2

To solve the equation $(7-x)(7+y) = 492-25$, we can start by simplifying the right side of the equation:

$492-25 = 467$.

So, the equation becomes:

$(7-x)(7+y) = 467$.

Now, we need to find values for $x$ and $y$ that satisfy this equation.

Let's start by factoring 467. It's a prime number, which means it only has two factors: 1 and itself. So, we can't break it down further.

Now, let's consider the left side of the equation $(7-x)(7+y)$. We have two factors here, and we need to find a combination of values for $x$ and $y$ that, when multiplied, gives us 467.

Let's try different combinations:

1. $7-x = 1$ and $7+y = 467$.

   Solving the first equation for $x$: $x = 7 - 1 = 6$. Solving the second equation for $y$: $y = 467 - 7 = 460$.

2. $7-x = 467$ and $7+y = 1$.

   Solving the first equation for $x$: $x = 7 - 467 = -460$. Solving the second equation for $y$: $y = 1 - 7 = -6$.

So, there are two possible solutions:

1. $x = 6$ and $y = 460$.
2. $x = -460$ and $y = -6$.

These are the pairs of values for $x$ and $y$ that satisfy the equation $(7-x)(7+y) = 492-25$.