Question

Школьный спортивный зал имеет следущие размеры . его ширина в 3 раза меньше длины , а высота совпадает с шириной . нацдите объём параллелепипеда , соответствуещего спортивному залу , если сумма всех упомянутых измерений состовляет 35 метров .

Answer 1

Х м - ширина и высота
3х м - длина
х+х+3х=35
5х=35
х=7(м) - ширина и высота
7*3=21(м) - длина
21*7*7=1029(м³) - объем помещения спортзала

Answer 2

Calculating the Volume of the School Sports Hall

To calculate the volume of the school sports hall, we can use the given information about its dimensions. Let's denote the length as L, the width as W, and the height as H. We are given the following relationships: - The width is 3 times smaller than the length: W = 1/3 * L - The height is equal to the width: H = W - The sum of all dimensions is 35 meters: L + W + H = 35

Calculating the Dimensions

First, let's express the width and height in terms of the length: - Width: W = 1/3 * L - Height: H = W = 1/3 * L

Now, we can substitute these expressions into the sum of dimensions equation: - L + 1/3 * L + 1/3 * L = 35 - 5/3 * L = 35 - L = 35 * 3 / 5 - L = 21

Now that we have the length, we can calculate the width and height: - Width: W = 1/3 * 21 = 7 - Height: H = 7

Calculating the Volume

The volume of a parallelepiped (rectangular prism) is given by the formula: V = L * W * H

Substituting the values we found: - V = 21 * 7 * 7 - V = 1029 cubic meters

So, the volume of the parallelepiped corresponding to the school sports hall is 1029 cubic meters.