Question

15/2+45/2= 6/1+8/3= 5/1-40/3= 8/3-7/1= 2 9/1+5 9/4= 3 5/4-2 5/3= 4 6/5-2 12/5=

Answer 1

$\frac{15}{2} + \frac{45}{2} = 30$

$\frac{6}{1} + \frac{8}{3} = \frac{26}{3} = 8 \frac{2}{3}$

$\frac{5}{1} - \frac{40}{3} = - \frac{25}{3} = - 8 \frac{1}{3}$

$\frac{8}{3} - \frac{7}{1} = - \frac{13}{3} = - 4 \frac{1}{3}$

$2( \frac{9}{4} ) + 5( \frac{9}{4} ) = \frac{117}{4 } = 29 \frac{1}{4}$

$3( \frac{5}{4} ) - 2( \frac{5}{3} ) = \frac{5}{12}$

$4( \frac{6}{5} ) - 2( \frac{12}{5} ) = 0$

Answer 2

Let's calculate each of the expressions:

1. $\frac{15}{2} + \frac{45}{2} = \frac{60}{2} = 30$

2. $\frac{6}{1} + \frac{8}{3} = 6 + \frac{8}{3} = \frac{18}{3} + \frac{8}{3} = \frac{26}{3}$

3. $\frac{5}{1} - \frac{40}{3} = 5 - \frac{40}{3} = \frac{15}{3} - \frac{40}{3} = \frac{-25}{3}$

4. $\frac{8}{3} - \frac{7}{1} = \frac{8}{3} - 7 = \frac{8}{3} - \frac{21}{3} = \frac{-13}{3}$

5. $2 \frac{9}{1} + 5 \frac{9}{4} = 2(9) + 5 \frac{9}{4} = 18 + 5 \frac{9}{4} = 18 + \frac{45}{4} = 18 + 11.25 = 29.25$

6. $3 \frac{5}{4} - 2 \frac{25}{3} = \frac{12}{4} + \frac{5}{4} - \frac{50}{3} = \frac{17}{4} - \frac{50}{3}$

To perform this subtraction, we need to find a common denominator:

$\frac{17}{4} \times \frac{3}{3} = \frac{51}{12}$

$\frac{50}{3} \times \frac{4}{4} = \frac{200}{12}$

Now we can subtract:

$\frac{51}{12} - \frac{200}{12} = \frac{-149}{12}$

7. $4 \frac{6}{5} - 2 \frac{12}{5} = \frac{26}{5} - \frac{24}{5} = \frac{2}{5}$

So, the results are:

1. $30$
2. $\frac{26}{3}$