Question

(2 13/48 + 2 5/12): 3 3/4 - 9 3/4 : 12 2 13/48 - ДРОБЬ

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve this expression, we'll first convert all the mixed numbers to improper fractions, then perform the operations step by step. Here's the breakdown:

1. Convert mixed numbers to improper fractions:
   • $2 \frac{13}{48}$ as an improper fraction is $\frac{97}{48}$.
   • $2 \frac{5}{12}$ as an improper fraction is $\frac{29}{12}$.
   • $3 \frac{3}{4}$ as an improper fraction is $\frac{15}{4}$.
   • $9 \frac{3}{4}$ as an improper fraction is $\frac{39}{4}$.
   • 12 \frac{2 \frac{13}{48} as an improper fraction is $\frac{157}{12}$.

Now, the expression becomes: $\frac{97}{48} + \frac{29}{12} : \frac{15}{4} - \frac{39}{4} : \frac{157}{12}$.

2. Perform the operations from left to right:

   a. Addition and Subtraction: $\frac{97}{48} + \frac{29}{12} = \frac{97}{48} + \frac{97}{48} = \frac{97 + 97}{48} = \frac{194}{48} = \frac{97}{24}$.

   b. Division: $\frac{97}{24} : \frac{15}{4} = \frac{97}{24} \cdot \frac{4}{15} = \frac{97 \cdot 4}{24 \cdot 15} = \frac{388}{360} = \frac{97}{90}$.

   c. Subtraction: $\frac{97}{90} - \frac{39}{4} = \frac{97}{90} - \frac{9 \cdot 39}{9 \cdot 4} = \frac{97}{90} - \frac{351}{36} = \frac{97}{90} - \frac{351}{90} = \frac{97 - 351}{90} = \frac{-254}{90} = -\frac{127}{45}$.

So, the final result is $-\frac{127}{45}$.