Question

(х+1) 2 – (х-2)(х+2)=7

Answer 1

$(x+1) 2 - (x-2)(x+2)=7$

$2x+2-x^2-4=7$

$x^2-2x+11=0$

$D=\sqrt{(-2)^{2}-4*11 } =\sqrt{-40}$

Ответ:  нет решений

Answer 2

To solve the equation (х+1)² - (х-2)(х+2) = 7, you can follow these steps:

1. Expand the expressions on both sides of the equation: (х+1)² - (х-2)(х+2) = 7 (x² + 2x + 1) - (x² - 4) = 7

Now, distribute the negative sign through the second term: x² + 2x + 1 - x² + 4 = 7

2. Simplify the equation by combining like terms: 2x + 5 = 7

3. Now, isolate the variable x by moving 5 to the other side of the equation by subtracting 5 from both sides: 2x + 5 - 5 = 7 - 5 2x = 2

4. Finally, divide both sides by 2 to solve for x: 2x/2 = 2/2 x = 1

So, the solution to the equation (х+1)² - (х-2)(х+2) = 7 is x = 1.