Question

4(х – 1) = 2(2х – 8) + 12

Answer 1

Ответ:

4(х – 1) = 2(2х – 8) + 12

4x-4 = 4x-16+12

-4 = -16+12

-4 = -4

Тотожність доведена

Answer 2

To solve this equation, let's simplify and solve for x step by step:

1. Distribute the values on both sides of the equation:

   $4(x - 1) = 2(2x - 8) + 12$

   $4x - 4 = 4x - 16 + 12$

2. Combine like terms:

   $4x - 4 = 4x - 4$

3. Subtract $4x$ from both sides to isolate the constant term:

   $-4 = -4$

After simplifying, we get a statement that is always true ($-4 = -4$). This implies that the equation has infinitely many solutions. In other words, any value of $x$ will satisfy the equation.