Question

По течению реки катер прошел 150 километров за 5 часов против течения и его скорость была на 12 километров меньше по течению какое расстояние катер прошел против течения за 3 часа

Answer 1

1) 150:5=30(км/ч)-по течению
2)30-12=18(км/ч)-против течения
3)18*3=54(км)-за 3 часа

Answer 2

Calculation of the Boat's Speed and Distance Traveled Against the Current

To calculate the distance traveled by the boat against the current in 3 hours, we first need to determine the boat's speed in still water. We are given that the boat traveled 150 kilometers in 5 hours against the current and that its speed was 12 kilometers per hour slower when going against the current.

Let's denote the boat's speed in still water as x kilometers per hour and the speed of the current as y kilometers per hour.

When the boat is traveling against the current, its effective speed is (x - y) kilometers per hour. We are told that this speed is 12 kilometers per hour slower than the boat's speed in still water, so we can set up the equation:

(x - y) = x - 12

Simplifying the equation, we get:

-y = -12

Solving for y, we find that the speed of the current is 12 kilometers per hour.

Now that we know the speed of the current, we can calculate the boat's speed in still water:

x = (x - y) + y = 12 + 12 = 24 kilometers per hour.

Therefore, the boat's speed in still water is 24 kilometers per hour.

To find the distance traveled by the boat against the current in 3 hours, we can use the formula:

Distance = Speed × Time

Substituting the values, we get:

Distance = 24 × 3 = 72 kilometers.

Therefore, the boat traveled 72 kilometers against the current in 3 hours.

Answer:

The boat traveled a distance of 72 kilometers against the current in 3 hours.