Question

(х²+7х)2+14(х²+6х)+49=0

Answer 1

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Answer 2

To solve the quadratic equation (x² + 7x)² + 14(x² + 6x) + 49 = 0, let's first simplify it step by step.

1. Expand the square terms: (x⁴ + 14x³ + 49x²) + 14(x² + 6x) + 49 = 0

2. Distribute 14 into the second term: x⁴ + 14x³ + 49x² + 14x² + 84x + 49 = 0

3. Combine like terms: x⁴ + 14x³ + 63x² + 84x + 49 = 0

Now, you have a quartic equation. Unfortunately, solving quartic equations directly can be quite complex and may involve using numerical methods or specialized software. If you need a numerical solution for specific values of x, you can use numerical methods like the Newton-Raphson method or numerical solvers in software like Mathematica or MATLAB.

Without specific numerical values, it's not possible to provide the exact solutions to this quartic equation. If you have specific values of x or if there are constraints on the values of x, please provide more information so that I can assist you further.