Question

2x+3y=1 x=? -3x-y=2 y=?

Answer 1

Ответ:

(-1; 1)

Пошаговое объяснение:

-3x - y = 2

-у = 2 + 3х

у = -2 - 3х

2х + 3*(-2 - 3х) = 1

2х - 6 - 9х = 1

-7х = 1 + 6

-7х = 7

х = 7/-7

х = -1

у = -2 - 3*(-1) = -2 + 3 = 1

Answer 2

To solve the system of equations:

1. 2x + 3y = 1
2. -3x - y = 2

You can use either the substitution method or the elimination method. Let's use the elimination method:

First, multiply both sides of equation (2) by 3 to make the coefficients of y in both equations cancel each other out when summed:

1. 2x + 3y = 1
2. -9x - 3y = 6

Now, add equation (1) and equation (2) together to eliminate the variable y:

(2x + 3y) + (-9x - 3y) = 1 + 6

Simplify the equation:

-7x = 7

Now, divide both sides by -7 to solve for x:

x = -7 / -7 x = 1

Now that you have found the value of x, you can substitute it back into either equation (1) or equation (2) to solve for y. Let's use equation (1):

2x + 3y = 1 2(1) + 3y = 1 2 + 3y = 1

Subtract 2 from both sides:

3y = 1 - 2 3y = -1

Now, divide both sides by 3 to solve for y:

y = -1 / 3

So, the solutions to the system of equations are: x = 1 y = -1/3