Question

НСД (x y) 4,12x-7,2 =99 і. 3,34 y -20,64=300

Answer 1

Ответ:

2)3,34у-20,64=300

3,34у=320,64

У=320,64:3,34

у=36

4,12х-7,2=99

4,12х=99+7,2

4,12х=106,2

х=106,2:4,12

х=25

Answer 2

It appears that you have provided two equations:

1. $4.12x - 7.2 = 99$
2. $3.34y - 20.64 = 300$

To solve for $x$ and $y$, you can use the following steps:

Step 1: Solve for $x$ in the first equation: $4.12x - 7.2 = 99$

Add 7.2 to both sides of the equation: $4.12x = 99 + 7.2$ $4.12x = 106.2$

Now, divide both sides by 4.12 to isolate $x$: $x = \frac{106.2}{4.12}$ $x \approx 25.73$

So, the value of $x$ is approximately 25.73.

Step 2: Solve for $y$ in the second equation: $3.34y - 20.64 = 300$

Add 20.64 to both sides of the equation: $3.34y = 300 + 20.64$ $3.34y = 320.64$

Now, divide both sides by 3.34 to isolate $y$: $y = \frac{320.64}{3.34}$ $y \approx 96.06$

So, the value of $y$ is approximately 96.06.

Therefore, the solutions to the system of equations are approximately $x \approx 25.73$ and $y \approx 96.06$.