Question

-+*=; *+*=; ++*+*(-)=?

Answer 1

Ответ:

x(x+z-y)+y(y-x-z)+(x-y+z)=x^2+zx-yx+y^2-xy-zy+x-y+z=x^2-2xy+y^2+zx-zy+x-y+z=(x-y)^2+zx-zy+x-y+z=(x-y)^2+z(x-y)+x-y+z=(x-y)^2+(x-y)(z+1)+z=(x-y)(x-y+z-1)+z

Пошаговое объяснение:

Answer 2

Спасибо большое!!!

;)

Answer 3

The expression you provided appears to be a combination of mathematical operators and symbols. Let's break it down step by step:

• • *=; is not a standard mathematical expression. It seems like a combination of operators and symbols without any operands.
• • • *=; is also not a valid mathematical expression for the same reason.

The third part, +++(-), seems to contain some mathematical operators. Let's break it down further:

• +++(-) can be interpreted as follows:
  • ++ represents an increment operator, but it's not clear what it's incrementing.
  • • represents the multiplication operator.
  • • represents the addition operator.
  • (-) is enclosed in parentheses but does not contain any operands.

Without a clear understanding of the operands and their values, it's impossible to calculate a numerical result for this expression. Please provide more context or clarify the expression so that I can help you further.