Question

2x⁵+3x⁴-x²-2x-4=(x²+1)(2x²+Ax²+Bx-4)​

Answer 1

Пошаговое объяснение:

гоогщадргшщшщащулашаашащащак

Answer 2

To find the values of A and B in the equation:

2x^5 + 3x^4 - x^2 - 2x - 4 = (x^2 + 1)(2x^2 + Ax^2 + Bx - 4)

We can start by multiplying the factors on the right-hand side and then comparing the coefficients of like terms on both sides of the equation.

First, let's multiply the factors on the right-hand side:

(x^2 + 1)(2x^2 + Ax^2 + Bx - 4) = (x^2)(2x^2 + Ax^2 + Bx - 4) + (1)(2x^2 + Ax^2 + Bx - 4)

Now, distribute the terms:

(x^2)(2x^2) + (x^2)(Ax^2) + (x^2)(Bx) - (x^2)(4) + (1)(2x^2) + (1)(Ax^2) + (1)(Bx) - (1)(4)

Simplify each term:

2x^4 + Ax^4 + Bx^3 - 4x^2 + 2x^2 + Ax^2 + Bx - 4

Now, combine like terms on the right-hand side:

(2x^4 + Ax^4) + Bx^3 + (-4x^2 + 2x^2 + Ax^2) + Bx - 4

Combine like terms further:

(2 + A)x^4 + Bx^3 + (-2 + A)x^2 + Bx - 4

Now, we can equate the coefficients of like terms on both sides of the equation:

2x^5 + 3x^4 - x^2 - 2x - 4 = (2 + A)x^4 + Bx^3 + (-2 + A)x^2 + Bx - 4

Now, let's compare coefficients term by term:

1. Coefficient of x^5 on the left: 2 Coefficient of x^5 on the right: 0 (since there is no x^5 term on the right)

Since there is no x^5 term on the right, we have:

2 = 0

This equation is not possible, which means there is no solution for A and B that satisfies the given equation. It's possible that there may be a mistake in the original equation or that the equation is not solvable as written. Please double-check the equation or provide additional information if needed.