Question

5) x8 – x4 + 2 = 0 x​

Answer 1

Ответ:

x8 – x4 + 2 = 0

x4 =t

t^2-t+2=0

D=( -1)^2-4*1*21-8=-7

решений нет!

Пошаговое объяснение:

Answer 2

Ответ:
1)x8 – x4 + 2 = 0 x​
2)v=x4
3)v2-v+2=0

Пошаговое объяснение:

Решения нету.

Answer 3

To solve the equation x^8 - x^4 + 2 = 0, you can use substitution to make it more manageable. Let's make a substitution:

Let y = x^4.

Now, your equation becomes:

y^2 - y + 2 = 0

This is a quadratic equation in terms of y. You can solve it using the quadratic formula:

y = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = -1, and c = 2. Plugging these values into the quadratic formula:

y = (-(-1) ± √((-1)^2 - 4(1)(2))) / (2(1))

y = (1 ± √(1 - 8)) / 2

Now, calculate the discriminant (the value inside the square root):

1 - 8 = -7

Since the discriminant is negative, there are no real solutions for y. This means there are no real solutions for x^4 either.

Therefore, the equation x^8 - x^4 + 2 = 0 has no real solutions.