Question

27. (1+2+3+...+1992+1993):1993;​

Answer 1

Ответ:

997

Пошаговое объяснение:

Сумма аричметической прогрессии (в скобках)

1993*1994/2

Значит, ответ 1994/2=997

Answer 2

To simplify the expression (1+2+3+...+1992+1993)/1993, you can use the formula for the sum of an arithmetic series:

The sum of the first n natural numbers is given by: S_n = (n/2) * (first_term + last_term)

In this case, the first term is 1, the last term is 1993, and there are 1993 terms in the sequence. So, you can calculate the sum as follows:

S_n = (1993/2) * (1 + 1993) S_n = (1993/2) * 1994

Now, you can divide this sum by 1993:

(1+2+3+...+1992+1993)/1993 = [(1993/2) * 1994] / 1993

Now, you can cancel out the 1993 in the numerator and denominator:

[(1993/2) * 1994] / 1993 = (1994/2)

Finally, simplify further:

(1994/2) = 997

So, (1+2+3+...+1992+1993)/1993 = 997.