Question

1) 3(4-х)+1=2(3-х)+6 2)(5-3х)-(7-2х)=-3-2х 3)2х-19=8-х 4)11-6х=31-10х​

Answer 1

Пошаговое объяснение:

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Answer 2

Let's solve each of these equations step by step:

1. $3(4-x) + 1 = 2(3-x) + 6$

First, distribute the constants:

$12 - 3x + 1 = 6 - 2x + 6$

Combine like terms:

$13 - 3x = 12 - 2x$

Subtract $12$ from both sides:

$-3x + 1 = -2x$

Now, subtract $-2x$ from both sides:

$-3x + 1 - (-2x) = 0$

$-3x + 2x + 1 = 0$

Combine like terms:

$-x + 1 = 0$

Now, add $x$ to both sides:

$-x + x + 1 = 0 + x$

$1 = x$

So, the solution to this equation is $x = 1$.

2. $5 - 3x - (7 - 2x) = -3 - 2x$

First, distribute the negative sign in front of the parentheses:

$5 - 3x - 7 + 2x = -3 - 2x$

Combine like terms:

$-2x - 2 = -3 - 2x$

Now, add $2x$ to both sides:

$-2x + 2x - 2 = -3 + 2x$

$-2 = -3 + 2x$

Add $3$ to both sides:

$-2 + 3 = 2x$

$1 = 2x$

Now, divide both sides by $2$:

$\frac{1}{2} = x$

So, the solution to this equation is $x = \frac{1}{2}$.

3. $2x - 19 = 8 - x$

First, add $x$ to both sides:

$2x + x - 19 = 8 - x + x$

$3x - 19 = 8$

Now, add $19$ to both sides:

$3x - 19 + 19 = 8 + 19$

$3x = 27$

Now, divide both sides by $3$:

$\frac{3x}{3} = \frac{27}{3}$

$x = 9$

So, the solution to this equation is $x = 9$.

4. $11 - 6x = 31 - 10x$

First, add $10x$ to both sides:

$11 - 6x + 10x = 31 - 10x + 10x$

$11 + 4x = 31$

Now, subtract $11$ from both sides:

$11 + 4x - 11 = 31 - 11$

$4x = 20$

Now, divide both sides by $4$:

$\frac{4x}{4} = \frac{20}{4}$

$x = 5$

So, the solution to this equation is $x = 5$.